Base | Representation |
---|---|
bin | 111000011010010000… |
… | …0011110010010110011 |
3 | 102120200110022020020221 |
4 | 1300310200132102303 |
5 | 3441043320342321 |
6 | 131352334513511 |
7 | 11515651054111 |
oct | 1606440362263 |
9 | 376613266227 |
10 | 121140012211 |
11 | 47414419179 |
12 | 1b589665897 |
13 | b5674372ca |
14 | 5c128dcab1 |
15 | 32400e1e41 |
hex | 1c3481e4b3 |
121140012211 has 2 divisors, whose sum is σ = 121140012212. Its totient is φ = 121140012210.
The previous prime is 121140012187. The next prime is 121140012239. The reversal of 121140012211 is 112210041121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121140012211 - 219 = 121139487923 is a prime.
It is a super-3 number, since 3×1211400122113 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (121140012271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60570006105 + 60570006106.
It is an arithmetic number, because the mean of its divisors is an integer number (60570006106).
Almost surely, 2121140012211 is an apocalyptic number.
121140012211 is a deficient number, since it is larger than the sum of its proper divisors (1).
121140012211 is an equidigital number, since it uses as much as digits as its factorization.
121140012211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 121140012211 its reverse (112210041121), we get a palindrome (233350053332).
The spelling of 121140012211 in words is "one hundred twenty-one billion, one hundred forty million, twelve thousand, two hundred eleven".
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