1211401977343 has 2 divisors, whose sum is σ = 1211401977344. Its totient is φ = 1211401977342.

The previous prime is 1211401977329. The next prime is 1211401977367. The reversal of 1211401977343 is 3437791041121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1211401977343 - 2⁵ = 1211401977311 is a prime.

It is a super-3 number, since 3×1211401977343³ (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1211401977343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211401978343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605700988671 + 605700988672.

It is an arithmetic number, because the mean of its divisors is an integer number (605700988672).

Almost surely, 2^{1211401977343} is an apocalyptic number.

1211401977343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211401977343 is an equidigital number, since it uses as much as digits as its factorization.

1211401977343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 127008, while the sum is 43.

The spelling of 1211401977343 in words is "one trillion, two hundred eleven billion, four hundred one million, nine hundred seventy-seven thousand, three hundred forty-three".