1211402004431 has 2 divisors, whose sum is σ = 1211402004432. Its totient is φ = 1211402004430.

The previous prime is 1211402004353. The next prime is 1211402004437. The reversal of 1211402004431 is 1344002041121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1211402004431 is a prime.

It is a super-3 number, since 3×1211402004431³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1211402004397 and 1211402004406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211402004437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605701002215 + 605701002216.

It is an arithmetic number, because the mean of its divisors is an integer number (605701002216).

Almost surely, 2^{1211402004431} is an apocalyptic number.

1211402004431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211402004431 is an equidigital number, since it uses as much as digits as its factorization.

1211402004431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1211402004431 its reverse (1344002041121), we get a palindrome (2555404045552).

The spelling of 1211402004431 in words is "one trillion, two hundred eleven billion, four hundred two million, four thousand, four hundred thirty-one".