12114043310 has 8 divisors (see below), whose sum is σ = 21805277976. Its totient is φ = 4845617320.

The previous prime is 12114043309. The next prime is 12114043343. The reversal of 12114043310 is 1334041121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×12114043310³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605702156 + ... + 605702175.

It is an arithmetic number, because the mean of its divisors is an integer number (2725659747).

Almost surely, 2^12114043310 is an apocalyptic number.

12114043310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12114043310 is a deficient number, since it is larger than the sum of its proper divisors (9691234666).

12114043310 is a wasteful number, since it uses less digits than its factorization.

12114043310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1211404338.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12114043310 its reverse (1334041121), we get a palindrome (13448084431).

The spelling of 12114043310 in words is "twelve billion, one hundred fourteen million, forty-three thousand, three hundred ten".