Base | Representation |
---|---|
bin | 111000011010010010… |
… | …0010100011100001111 |
3 | 102120200112012110021102 |
4 | 1300310210110130033 |
5 | 3441044100123211 |
6 | 131352412253315 |
7 | 11515662453404 |
oct | 1606444243417 |
9 | 376615173242 |
10 | 121141020431 |
11 | 47414a47712 |
12 | 1b589a7123b |
13 | b5676cb1a2 |
14 | 5c12ac22ab |
15 | 3240240a3b |
hex | 1c3491470f |
121141020431 has 2 divisors, whose sum is σ = 121141020432. Its totient is φ = 121141020430.
The previous prime is 121141020373. The next prime is 121141020437. The reversal of 121141020431 is 134020141121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121141020431 - 218 = 121140758287 is a prime.
It is a super-3 number, since 3×1211410204313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121141020437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60570510215 + 60570510216.
It is an arithmetic number, because the mean of its divisors is an integer number (60570510216).
Almost surely, 2121141020431 is an apocalyptic number.
121141020431 is a deficient number, since it is larger than the sum of its proper divisors (1).
121141020431 is an equidigital number, since it uses as much as digits as its factorization.
121141020431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 121141020431 its reverse (134020141121), we get a palindrome (255161161552).
The spelling of 121141020431 in words is "one hundred twenty-one billion, one hundred forty-one million, twenty thousand, four hundred thirty-one".
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