Base | Representation |
---|---|
bin | 11011100010110101011100… |
… | …010110101001011001101110 |
3 | 120212220222100200112222022120 |
4 | 123202311130112221121232 |
5 | 111334233434104234202 |
6 | 1105351242021253410 |
7 | 34342104303306303 |
oct | 3342653426513156 |
9 | 525828320488276 |
10 | 121141102024302 |
11 | 3566571aa50428 |
12 | 11705b59b64266 |
13 | 5279731696689 |
14 | 21cb39120d0aa |
15 | e012587240bc |
hex | 6e2d5c5a966e |
121141102024302 has 16 divisors (see below), whose sum is σ = 242282344352592. Its totient is φ = 40380343957440.
The previous prime is 121141102024279. The next prime is 121141102024361. The reversal of 121141102024302 is 203420201141121.
It is a super-3 number, since 3×1211411020243023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7844802 + ... + 17430522.
It is an arithmetic number, because the mean of its divisors is an integer number (15142646522037).
Almost surely, 2121141102024302 is an apocalyptic number.
121141102024302 is an abundant number, since it is smaller than the sum of its proper divisors (121141242328290).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121141102024302 is a wasteful number, since it uses less digits than its factorization.
121141102024302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11692003.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 121141102024302 its reverse (203420201141121), we get a palindrome (324561303165423).
The spelling of 121141102024302 in words is "one hundred twenty-one trillion, one hundred forty-one billion, one hundred two million, twenty-four thousand, three hundred two".
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