Base | Representation |
---|---|
bin | 11011100010110110010010… |
… | …000111110011001101011111 |
3 | 120212221001200112222021021001 |
4 | 123202312102013303031133 |
5 | 111334242311022230413 |
6 | 1105351511324051131 |
7 | 34342135535660344 |
oct | 3342662207631537 |
9 | 525831615867231 |
10 | 121142004101983 |
11 | 35666043171777 |
12 | 11706170093aa7 |
13 | 5279846539957 |
14 | 21cb438d4a7cb |
15 | e012aca114dd |
hex | 6e2d921f335f |
121142004101983 has 2 divisors, whose sum is σ = 121142004101984. Its totient is φ = 121142004101982.
The previous prime is 121142004101971. The next prime is 121142004102017. The reversal of 121142004101983 is 389101400241121.
It is a weak prime.
It is an emirp because it is prime and its reverse (389101400241121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121142004101983 is a prime.
It is a super-3 number, since 3×1211420041019833 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121142004102983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60571002050991 + 60571002050992.
It is an arithmetic number, because the mean of its divisors is an integer number (60571002050992).
Almost surely, 2121142004101983 is an apocalyptic number.
121142004101983 is a deficient number, since it is larger than the sum of its proper divisors (1).
121142004101983 is an equidigital number, since it uses as much as digits as its factorization.
121142004101983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 37.
The spelling of 121142004101983 in words is "one hundred twenty-one trillion, one hundred forty-two billion, four million, one hundred one thousand, nine hundred eighty-three".
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