Base | Representation |
---|---|
bin | 10110100100001000… |
… | …00001000110100111 |
3 | 1011021021000021110221 |
4 | 23102010001012213 |
5 | 144302213444142 |
6 | 5322025225211 |
7 | 606126012142 |
oct | 132204010647 |
9 | 34237007427 |
10 | 12114203047 |
11 | 5157174061 |
12 | 2421032207 |
13 | 11b0a0bcab |
14 | 82cc69059 |
15 | 4ad7cd767 |
hex | 2d21011a7 |
12114203047 has 8 divisors (see below), whose sum is σ = 12673708992. Its totient is φ = 11567270400.
The previous prime is 12114203029. The next prime is 12114203069. The reversal of 12114203047 is 74030241121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12114203047 - 223 = 12105814439 is a prime.
It is a super-3 number, since 3×121142030473 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12114203347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3141354 + ... + 3145207.
It is an arithmetic number, because the mean of its divisors is an integer number (1584213624).
Almost surely, 212114203047 is an apocalyptic number.
12114203047 is a deficient number, since it is larger than the sum of its proper divisors (559505945).
12114203047 is an equidigital number, since it uses as much as digits as its factorization.
12114203047 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6286649.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12114203047 its reverse (74030241121), we get a palindrome (86144444168).
The spelling of 12114203047 in words is "twelve billion, one hundred fourteen million, two hundred three thousand, forty-seven".
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