Base | Representation |
---|---|
bin | 111000011010010100… |
… | …1001101110100101011 |
3 | 102120200121121200001121 |
4 | 1300310221031310223 |
5 | 3441044412212133 |
6 | 131352500000111 |
7 | 11516006410615 |
oct | 1606451156453 |
9 | 376617550047 |
10 | 121142304043 |
11 | 47415744052 |
12 | 1b58a390037 |
13 | b567a5a517 |
14 | 5c12d37db5 |
15 | 32403e602d |
hex | 1c34a4dd2b |
121142304043 has 2 divisors, whose sum is σ = 121142304044. Its totient is φ = 121142304042.
The previous prime is 121142304001. The next prime is 121142304047. The reversal of 121142304043 is 340403241121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121142304043 is a prime.
It is a super-3 number, since 3×1211423040433 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121142303999 and 121142304017.
It is not a weakly prime, because it can be changed into another prime (121142304047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60571152021 + 60571152022.
It is an arithmetic number, because the mean of its divisors is an integer number (60571152022).
Almost surely, 2121142304043 is an apocalyptic number.
121142304043 is a deficient number, since it is larger than the sum of its proper divisors (1).
121142304043 is an equidigital number, since it uses as much as digits as its factorization.
121142304043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 121142304043 its reverse (340403241121), we get a palindrome (461545545164).
The spelling of 121142304043 in words is "one hundred twenty-one billion, one hundred forty-two million, three hundred four thousand, forty-three".
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