Base | Representation |
---|---|
bin | 10001101000001110100… |
… | …000001100111010111111 |
3 | 11021210220020011112002102 |
4 | 101220032200030322333 |
5 | 124321444032200111 |
6 | 2324304234415315 |
7 | 153344134644065 |
oct | 21501640147277 |
9 | 4253806145072 |
10 | 1211424100031 |
11 | 427842360582 |
12 | 17694759153b |
13 | 8a310341302 |
14 | 428c1874035 |
15 | 217a2aee13b |
hex | 11a0e80cebf |
1211424100031 has 2 divisors, whose sum is σ = 1211424100032. Its totient is φ = 1211424100030.
The previous prime is 1211424099973. The next prime is 1211424100037. The reversal of 1211424100031 is 1300014241121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211424100031 - 222 = 1211419905727 is a prime.
It is a super-3 number, since 3×12114241000313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1211424099976 and 1211424100012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211424100037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605712050015 + 605712050016.
It is an arithmetic number, because the mean of its divisors is an integer number (605712050016).
Almost surely, 21211424100031 is an apocalyptic number.
1211424100031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211424100031 is an equidigital number, since it uses as much as digits as its factorization.
1211424100031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1211424100031 its reverse (1300014241121), we get a palindrome (2511438341152).
The spelling of 1211424100031 in words is "one trillion, two hundred eleven billion, four hundred twenty-four million, one hundred thousand, thirty-one".
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