1211424442013 has 2 divisors, whose sum is σ = 1211424442014. Its totient is φ = 1211424442012.

The previous prime is 1211424441989. The next prime is 1211424442057. The reversal of 1211424442013 is 3102444241121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1209003605209 + 2420836804 = 1099547^2 + 49202^2 .

It is an emirp because it is prime and its reverse (3102444241121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1211424442013 - 2²⁰ = 1211423393437 is a prime.

It is a super-3 number, since 3×1211424442013³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211424442073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605712221006 + 605712221007.

It is an arithmetic number, because the mean of its divisors is an integer number (605712221007).

Almost surely, 2^{1211424442013} is an apocalyptic number.

It is an amenable number.

1211424442013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211424442013 is an equidigital number, since it uses as much as digits as its factorization.

1211424442013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 1211424442013 its reverse (3102444241121), we get a palindrome (4313868683134).

The spelling of 1211424442013 in words is "one trillion, two hundred eleven billion, four hundred twenty-four million, four hundred forty-two thousand, thirteen".