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1211430250021 is a prime number
BaseRepresentation
bin10001101000001110110…
…111101010011000100101
311021210220122201222021211
4101220032313222120211
5124322002121000041
62324305014311421
7153344241140065
oct21501667523045
94253818658254
101211430250021
11427845881112
12176949658571
138a3116b5664
14428c25d53a5
15217a3416481
hex11a0edea625

1211430250021 has 2 divisors, whose sum is σ = 1211430250022. Its totient is φ = 1211430250020.

The previous prime is 1211430250007. The next prime is 1211430250061. The reversal of 1211430250021 is 1200520341121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 705213652900 + 506216597121 = 839770^2 + 711489^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211430250021 - 25 = 1211430249989 is a prime.

It is a super-3 number, since 3×12114302500213 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211430249974 and 1211430250001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211430250061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605715125010 + 605715125011.

It is an arithmetic number, because the mean of its divisors is an integer number (605715125011).

Almost surely, 21211430250021 is an apocalyptic number.

It is an amenable number.

1211430250021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211430250021 is an equidigital number, since it uses as much as digits as its factorization.

1211430250021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 1211430250021 its reverse (1200520341121), we get a palindrome (2411950591142).

The spelling of 1211430250021 in words is "one trillion, two hundred eleven billion, four hundred thirty million, two hundred fifty thousand, twenty-one".