Base | Representation |
---|---|
bin | 10001101000001111101… |
… | …101010001100101100011 |
3 | 11021210221122012000000222 |
4 | 101220033231101211203 |
5 | 124322014220213402 |
6 | 2324310235433255 |
7 | 153344501453333 |
oct | 21501755214543 |
9 | 4253848160028 |
10 | 1211444304227 |
11 | 427852800263 |
12 | 1769522b582b |
13 | 8a314596661 |
14 | 428c44130c3 |
15 | 217a47907a2 |
hex | 11a0fb51963 |
1211444304227 has 2 divisors, whose sum is σ = 1211444304228. Its totient is φ = 1211444304226.
The previous prime is 1211444304193. The next prime is 1211444304229. The reversal of 1211444304227 is 7224034441121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211444304227 - 210 = 1211444303203 is a prime.
It is a super-3 number, since 3×12114443042273 (a number of 37 digits) contains 333 as substring.
Together with 1211444304229, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1211444304229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605722152113 + 605722152114.
It is an arithmetic number, because the mean of its divisors is an integer number (605722152114).
Almost surely, 21211444304227 is an apocalyptic number.
1211444304227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211444304227 is an equidigital number, since it uses as much as digits as its factorization.
1211444304227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 1211444304227 its reverse (7224034441121), we get a palindrome (8435478745348).
The spelling of 1211444304227 in words is "one trillion, two hundred eleven billion, four hundred forty-four million, three hundred four thousand, two hundred twenty-seven".
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