Base | Representation |
---|---|
bin | 11011100010111111000001… |
… | …101010110100010001111011 |
3 | 120212221221220210110221201121 |
4 | 123202333001222310101323 |
5 | 111334421022241321042 |
6 | 1105400103033530111 |
7 | 34342620266426401 |
oct | 3342770152642173 |
9 | 525857823427647 |
10 | 121151391745147 |
11 | 3566a020258a55 |
12 | 11707b4bb73937 |
13 | 527a6b13c2caa |
14 | 21cba89a2b471 |
15 | e0165bc60367 |
hex | 6e2fc1ab447b |
121151391745147 has 2 divisors, whose sum is σ = 121151391745148. Its totient is φ = 121151391745146.
The previous prime is 121151391745121. The next prime is 121151391745169. The reversal of 121151391745147 is 741547193151121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121151391745147 - 223 = 121151383356539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121151391745094 and 121151391745103.
It is not a weakly prime, because it can be changed into another prime (121151392745147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60575695872573 + 60575695872574.
It is an arithmetic number, because the mean of its divisors is an integer number (60575695872574).
Almost surely, 2121151391745147 is an apocalyptic number.
121151391745147 is a deficient number, since it is larger than the sum of its proper divisors (1).
121151391745147 is an equidigital number, since it uses as much as digits as its factorization.
121151391745147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1058400, while the sum is 52.
The spelling of 121151391745147 in words is "one hundred twenty-one trillion, one hundred fifty-one billion, three hundred ninety-one million, seven hundred forty-five thousand, one hundred forty-seven".
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