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121157898301403 is a prime number
BaseRepresentation
bin11011100011000101000101…
…011111010110111111011011
3120212222120201020201020221122
4123203011011133112333123
5111340022333431121103
61105403100423555455
734343240444306225
oct3343050537267733
9525876636636848
10121157898301403
113567185a013a77
1211709266bbbb8b
13527b1aa3cb092
1421cc105c1b415
15e018dd0a8b38
hex6e31457d6fdb

121157898301403 has 2 divisors, whose sum is σ = 121157898301404. Its totient is φ = 121157898301402.

The previous prime is 121157898301387. The next prime is 121157898301459. The reversal of 121157898301403 is 304103898751121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121157898301403 - 24 = 121157898301387 is a prime.

It is a super-3 number, since 3×1211578983014033 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (121157898309403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60578949150701 + 60578949150702.

It is an arithmetic number, because the mean of its divisors is an integer number (60578949150702).

Almost surely, 2121157898301403 is an apocalyptic number.

121157898301403 is a deficient number, since it is larger than the sum of its proper divisors (1).

121157898301403 is an equidigital number, since it uses as much as digits as its factorization.

121157898301403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 53.

The spelling of 121157898301403 in words is "one hundred twenty-one trillion, one hundred fifty-seven billion, eight hundred ninety-eight million, three hundred one thousand, four hundred three".