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121171433 is a prime number
BaseRepresentation
bin1110011100011…
…10110111101001
322110000010221212
413032032313221
5222004441213
620005042505
73000640325
oct716166751
9273003855
10121171433
1162441989
12346b6435
131c147196
1412142985
15a9879a8
hex738ede9

121171433 has 2 divisors, whose sum is σ = 121171434. Its totient is φ = 121171432.

The previous prime is 121171423. The next prime is 121171447. The reversal of 121171433 is 334171121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120187369 + 984064 = 10963^2 + 992^2 .

It is a cyclic number.

It is not a de Polignac number, because 121171433 - 212 = 121167337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121171399 and 121171408.

It is not a weakly prime, because it can be changed into another prime (121171423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60585716 + 60585717.

It is an arithmetic number, because the mean of its divisors is an integer number (60585717).

Almost surely, 2121171433 is an apocalyptic number.

It is an amenable number.

121171433 is a deficient number, since it is larger than the sum of its proper divisors (1).

121171433 is an equidigital number, since it uses as much as digits as its factorization.

121171433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 504, while the sum is 23.

The square root of 121171433 is about 11007.7896509699. The cubic root of 121171433 is about 494.8422215914.

The spelling of 121171433 in words is "one hundred twenty-one million, one hundred seventy-one thousand, four hundred thirty-three".