Base | Representation |
---|---|
bin | 111000011100000010… |
… | …1010110111101010101 |
3 | 102120211122012121001121 |
4 | 1300320011112331111 |
5 | 3441204200410031 |
6 | 131402320523541 |
7 | 11520310053664 |
oct | 1607005267525 |
9 | 376748177047 |
10 | 121200013141 |
11 | 4744527a819 |
12 | 1b5a57805b1 |
13 | b5769b480c |
14 | 5c1a87addb |
15 | 32454e5011 |
hex | 1c38156f55 |
121200013141 has 2 divisors, whose sum is σ = 121200013142. Its totient is φ = 121200013140.
The previous prime is 121200013127. The next prime is 121200013223. The reversal of 121200013141 is 141310002121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 62367570225 + 58832442916 = 249735^2 + 242554^2 .
It is a cyclic number.
It is not a de Polignac number, because 121200013141 - 215 = 121199980373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121200013841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600006570 + 60600006571.
It is an arithmetic number, because the mean of its divisors is an integer number (60600006571).
Almost surely, 2121200013141 is an apocalyptic number.
It is an amenable number.
121200013141 is a deficient number, since it is larger than the sum of its proper divisors (1).
121200013141 is an equidigital number, since it uses as much as digits as its factorization.
121200013141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 121200013141 its reverse (141310002121), we get a palindrome (262510015262).
The spelling of 121200013141 in words is "one hundred twenty-one billion, two hundred million, thirteen thousand, one hundred forty-one".
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