Base | Representation |
---|---|
bin | 1011000001011110100011… |
… | …1001011000110110001111 |
3 | 1120220122212100020212001002 |
4 | 2300113220321120312033 |
5 | 3042033240041200421 |
6 | 41435504503010515 |
7 | 2360433102022214 |
oct | 260275071306617 |
9 | 46818770225032 |
10 | 12120010100111 |
11 | 3953081808321 |
12 | 1438b32a39a3b |
13 | 69bbb1a02244 |
14 | 2dc87c3d3b0b |
15 | 160408c1db0b |
hex | b05e8e58d8f |
12120010100111 has 2 divisors, whose sum is σ = 12120010100112. Its totient is φ = 12120010100110.
The previous prime is 12120010100071. The next prime is 12120010100119. The reversal of 12120010100111 is 11100101002121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12120010100111 - 242 = 7721963589007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12120010100092 and 12120010100101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12120010100119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060005050055 + 6060005050056.
It is an arithmetic number, because the mean of its divisors is an integer number (6060005050056).
Almost surely, 212120010100111 is an apocalyptic number.
12120010100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120010100111 is an equidigital number, since it uses as much as digits as its factorization.
12120010100111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 12120010100111 its reverse (11100101002121), we get a palindrome (23220111102232).
The spelling of 12120010100111 in words is "twelve trillion, one hundred twenty billion, ten million, one hundred thousand, one hundred eleven".
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