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12120010101223 is a prime number
BaseRepresentation
bin1011000001011110100011…
…1001011001000111100111
31120220122212100020220120021
42300113220321121013213
53042033240041214343
641435504503020011
72360433102025363
oct260275071310747
946818770226507
1012120010101223
113953081809142
121438b32a3a607
1369bbb1a028bb
142dc87c3d42a3
15160408c1e0ed
hexb05e8e591e7

12120010101223 has 2 divisors, whose sum is σ = 12120010101224. Its totient is φ = 12120010101222.

The previous prime is 12120010101193. The next prime is 12120010101259. The reversal of 12120010101223 is 32210101002121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12120010101223 - 217 = 12120009970151 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12120010101197 and 12120010101206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120010101263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060005050611 + 6060005050612.

It is an arithmetic number, because the mean of its divisors is an integer number (6060005050612).

Almost surely, 212120010101223 is an apocalyptic number.

12120010101223 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120010101223 is an equidigital number, since it uses as much as digits as its factorization.

12120010101223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12120010101223 its reverse (32210101002121), we get a palindrome (44330111103344).

The spelling of 12120010101223 in words is "twelve trillion, one hundred twenty billion, ten million, one hundred one thousand, two hundred twenty-three".