Base | Representation |
---|---|
bin | 111000011100000011… |
… | …0000111010000111011 |
3 | 102120211122120122110211 |
4 | 1300320012013100323 |
5 | 3441204223223003 |
6 | 131402325051551 |
7 | 11520311536564 |
oct | 1607006072073 |
9 | 376748518424 |
10 | 121200211003 |
11 | 474453a5443 |
12 | 1b5a5856bb7 |
13 | b576a538b1 |
14 | 5c1a8cd16b |
15 | 324553396d |
hex | 1c3818743b |
121200211003 has 2 divisors, whose sum is σ = 121200211004. Its totient is φ = 121200211002.
The previous prime is 121200210997. The next prime is 121200211049. The reversal of 121200211003 is 300112002121.
It is a weak prime.
It is an emirp because it is prime and its reverse (300112002121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121200211003 - 233 = 112610276411 is a prime.
It is a super-2 number, since 2×1212002110032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121200241003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600105501 + 60600105502.
It is an arithmetic number, because the mean of its divisors is an integer number (60600105502).
Almost surely, 2121200211003 is an apocalyptic number.
121200211003 is a deficient number, since it is larger than the sum of its proper divisors (1).
121200211003 is an equidigital number, since it uses as much as digits as its factorization.
121200211003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 121200211003 its reverse (300112002121), we get a palindrome (421312213124).
The spelling of 121200211003 in words is "one hundred twenty-one billion, two hundred million, two hundred eleven thousand, three".
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