Base | Representation |
---|---|
bin | 1011000001011110101000… |
… | …0110011100011100101011 |
3 | 1120220122220202021010000011 |
4 | 2300113222012130130223 |
5 | 3042033310224044242 |
6 | 41435510503552351 |
7 | 2360433435512653 |
oct | 260275206343453 |
9 | 46818822233004 |
10 | 12120030299947 |
11 | 39530921547a9 |
12 | 1438b3975b6b7 |
13 | 69bbb5c555cb |
14 | 2dc880d71363 |
15 | 16040a8add17 |
hex | b05ea19c72b |
12120030299947 has 2 divisors, whose sum is σ = 12120030299948. Its totient is φ = 12120030299946.
The previous prime is 12120030299939. The next prime is 12120030299959. The reversal of 12120030299947 is 74999203002121.
It is a happy number.
12120030299947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (74999203002121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12120030299947 - 23 = 12120030299939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12120030299947.
It is not a weakly prime, because it can be changed into another prime (12120030299647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060015149973 + 6060015149974.
It is an arithmetic number, because the mean of its divisors is an integer number (6060015149974).
Almost surely, 212120030299947 is an apocalyptic number.
12120030299947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120030299947 is an equidigital number, since it uses as much as digits as its factorization.
12120030299947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 489888, while the sum is 49.
The spelling of 12120030299947 in words is "twelve trillion, one hundred twenty billion, thirty million, two hundred ninety-nine thousand, nine hundred forty-seven".
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