Base | Representation |
---|---|
bin | 1011000001011110101000… |
… | …0110011100100001111011 |
3 | 1120220122220202021010110121 |
4 | 2300113222012130201323 |
5 | 3042033310224102113 |
6 | 41435510503554111 |
7 | 2360433435513643 |
oct | 260275206344173 |
9 | 46818822233417 |
10 | 12120030300283 |
11 | 3953092154a84 |
12 | 1438b3975b937 |
13 | 69bbb5c557c9 |
14 | 2dc880d71523 |
15 | 16040a8ade8d |
hex | b05ea19c87b |
12120030300283 has 2 divisors, whose sum is σ = 12120030300284. Its totient is φ = 12120030300282.
The previous prime is 12120030300247. The next prime is 12120030300349. The reversal of 12120030300283 is 38200303002121.
12120030300283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12120030300283 is a prime.
It is not a weakly prime, because it can be changed into another prime (12120030300683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060015150141 + 6060015150142.
It is an arithmetic number, because the mean of its divisors is an integer number (6060015150142).
Almost surely, 212120030300283 is an apocalyptic number.
12120030300283 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120030300283 is an equidigital number, since it uses as much as digits as its factorization.
12120030300283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
The spelling of 12120030300283 in words is "twelve trillion, one hundred twenty billion, thirty million, three hundred thousand, two hundred eighty-three".
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