1212012010117 has 2 divisors, whose sum is σ = 1212012010118. Its totient is φ = 1212012010116.

The previous prime is 1212012010043. The next prime is 1212012010123. The reversal of 1212012010117 is 7110102102121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 832594201156 + 379417808961 = 912466^2 + 615969^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212012010117 - 2¹¹ = 1212012008069 is a prime.

It is a super-2 number, since 2×1212012010117² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1212012010094 and 1212012010103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212012011117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606006005058 + 606006005059.

It is an arithmetic number, because the mean of its divisors is an integer number (606006005059).

Almost surely, 2^{1212012010117} is an apocalyptic number.

It is an amenable number.

1212012010117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212012010117 is an equidigital number, since it uses as much as digits as its factorization.

1212012010117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1212012010117 its reverse (7110102102121), we get a palindrome (8322114112238).

The spelling of 1212012010117 in words is "one trillion, two hundred twelve billion, twelve million, ten thousand, one hundred seventeen".