Base | Representation |
---|---|
bin | 1011000001011110111101… |
… | …1101000101001011110001 |
3 | 1120220200011000021110000121 |
4 | 2300113233131011023301 |
5 | 3042034001222320144 |
6 | 41435523433050241 |
7 | 2360435606126104 |
oct | 260275735051361 |
9 | 46820130243017 |
10 | 12120120120049 |
11 | 3953128922997 |
12 | 1438b63856981 |
13 | 69bbcb7436b6 |
14 | 2dc88cc7273b |
15 | 160413702384 |
hex | b05ef7452f1 |
12120120120049 has 2 divisors, whose sum is σ = 12120120120050. Its totient is φ = 12120120120048.
The previous prime is 12120120119977. The next prime is 12120120120089. The reversal of 12120120120049 is 94002102102121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11668079044449 + 452041075600 = 3415857^2 + 672340^2 .
It is a cyclic number.
It is not a de Polignac number, because 12120120120049 - 243 = 3324027097841 is a prime.
It is not a weakly prime, because it can be changed into another prime (12120120120089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060060060024 + 6060060060025.
It is an arithmetic number, because the mean of its divisors is an integer number (6060060060025).
Almost surely, 212120120120049 is an apocalyptic number.
It is an amenable number.
12120120120049 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120120120049 is an equidigital number, since it uses as much as digits as its factorization.
12120120120049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
The spelling of 12120120120049 in words is "twelve trillion, one hundred twenty billion, one hundred twenty million, one hundred twenty thousand, forty-nine".
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