Base | Representation |
---|---|
bin | 1011000001011110111110… |
… | …0100001100101100101101 |
3 | 1120220200011010210020101212 |
4 | 2300113233210030230231 |
5 | 3042034002212021322 |
6 | 41435523541044205 |
7 | 2360435631026525 |
oct | 260275744145455 |
9 | 46820133706355 |
10 | 12120121985837 |
11 | 3953129987768 |
12 | 1438b643b6665 |
13 | 69bbcbc47a08 |
14 | 2dc88d1da685 |
15 | 1604139700e2 |
hex | b05ef90cb2d |
12120121985837 has 2 divisors, whose sum is σ = 12120121985838. Its totient is φ = 12120121985836.
The previous prime is 12120121985789. The next prime is 12120121985903. The reversal of 12120121985837 is 73858912102121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10609260638596 + 1510861347241 = 3257186^2 + 1229171^2 .
It is a cyclic number.
It is not a de Polignac number, because 12120121985837 - 26 = 12120121985773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12120121985137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060060992918 + 6060060992919.
It is an arithmetic number, because the mean of its divisors is an integer number (6060060992919).
Almost surely, 212120121985837 is an apocalyptic number.
It is an amenable number.
12120121985837 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120121985837 is an equidigital number, since it uses as much as digits as its factorization.
12120121985837 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 483840, while the sum is 50.
The spelling of 12120121985837 in words is "twelve trillion, one hundred twenty billion, one hundred twenty-one million, nine hundred eighty-five thousand, eight hundred thirty-seven".
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