Base | Representation |
---|---|
bin | 11011100011101101100000… |
… | …101000010101011100001011 |
3 | 120220010201202012220021001212 |
4 | 123203231200220111130023 |
5 | 111341230232121442024 |
6 | 1105435035440003335 |
7 | 34346335165644101 |
oct | 3343554050253413 |
9 | 526121665807055 |
10 | 121201303312139 |
11 | 3568920300aa76 |
12 | 1171575b30054b |
13 | 5282306a3c09b |
14 | 21d02626dbc71 |
15 | e02acd987a0e |
hex | 6e3b60a1570b |
121201303312139 has 2 divisors, whose sum is σ = 121201303312140. Its totient is φ = 121201303312138.
The previous prime is 121201303312129. The next prime is 121201303312153. The reversal of 121201303312139 is 931213303102121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121201303312139 - 24 = 121201303312123 is a prime.
It is a super-2 number, since 2×1212013033121392 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121201303312129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600651656069 + 60600651656070.
It is an arithmetic number, because the mean of its divisors is an integer number (60600651656070).
Almost surely, 2121201303312139 is an apocalyptic number.
121201303312139 is a deficient number, since it is larger than the sum of its proper divisors (1).
121201303312139 is an equidigital number, since it uses as much as digits as its factorization.
121201303312139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 121201303312139 in words is "one hundred twenty-one trillion, two hundred one billion, three hundred three million, three hundred twelve thousand, one hundred thirty-nine".
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