Base | Representation |
---|---|
bin | 11011100011110101100110… |
… | …100111001101000001011011 |
3 | 120220011120011212020022021122 |
4 | 123203311212213031001123 |
5 | 111341401031331112103 |
6 | 1105443034035155455 |
7 | 34350063431202302 |
oct | 3343654647150133 |
9 | 526146155208248 |
10 | 121209993613403 |
11 | 35691962502a32 |
12 | 11717385745b8b |
13 | 52830902a6b96 |
14 | 21d0848937439 |
15 | e02e3b88bb38 |
hex | 6e3d669cd05b |
121209993613403 has 2 divisors, whose sum is σ = 121209993613404. Its totient is φ = 121209993613402.
The previous prime is 121209993613351. The next prime is 121209993613433. The reversal of 121209993613403 is 304316399902121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121209993613403 - 28 = 121209993613147 is a prime.
It is a super-2 number, since 2×1212099936134032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121209993613433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60604996806701 + 60604996806702.
It is an arithmetic number, because the mean of its divisors is an integer number (60604996806702).
Almost surely, 2121209993613403 is an apocalyptic number.
121209993613403 is a deficient number, since it is larger than the sum of its proper divisors (1).
121209993613403 is an equidigital number, since it uses as much as digits as its factorization.
121209993613403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1889568, while the sum is 53.
The spelling of 121209993613403 in words is "one hundred twenty-one trillion, two hundred nine billion, nine hundred ninety-three million, six hundred thirteen thousand, four hundred three".
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