Base | Representation |
---|---|
bin | 10001101000110110110… |
… | …110010111101101110011 |
3 | 11021212122101212121100112 |
4 | 101220312312113231303 |
5 | 124324340324000201 |
6 | 2324455335011535 |
7 | 153366664335404 |
oct | 21506666275563 |
9 | 4255571777315 |
10 | 1212101000051 |
11 | 42805a462587 |
12 | 176ab6209bab |
13 | 8a3ba653276 |
14 | 429477179ab |
15 | 217e225c0bb |
hex | 11a36d97b73 |
1212101000051 has 2 divisors, whose sum is σ = 1212101000052. Its totient is φ = 1212101000050.
The previous prime is 1212101000023. The next prime is 1212101000113. The reversal of 1212101000051 is 1500001012121.
It is a weak prime.
It is an emirp because it is prime and its reverse (1500001012121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212101000051 is a prime.
It is not a weakly prime, because it can be changed into another prime (1212101000021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606050500025 + 606050500026.
It is an arithmetic number, because the mean of its divisors is an integer number (606050500026).
Almost surely, 21212101000051 is an apocalyptic number.
1212101000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212101000051 is an equidigital number, since it uses as much as digits as its factorization.
1212101000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 1212101000051 its reverse (1500001012121), we get a palindrome (2712102012172).
The spelling of 1212101000051 in words is "one trillion, two hundred twelve billion, one hundred one million, fifty-one", and thus it is an aban number.
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