1212101000113 has 2 divisors, whose sum is σ = 1212101000114. Its totient is φ = 1212101000112.

The previous prime is 1212101000051. The next prime is 1212101000213. The reversal of 1212101000113 is 3110001012121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 940234697649 + 271866302464 = 969657^2 + 521408^2 .

It is an emirp because it is prime and its reverse (3110001012121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1212101000113 - 2²¹ = 1212098902961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212101000093 and 1212101000102.

It is not a weakly prime, because it can be changed into another prime (1212101000213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606050500056 + 606050500057.

It is an arithmetic number, because the mean of its divisors is an integer number (606050500057).

Almost surely, 2^{1212101000113} is an apocalyptic number.

It is an amenable number.

1212101000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212101000113 is an equidigital number, since it uses as much as digits as its factorization.

1212101000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1212101000113 its reverse (3110001012121), we get a palindrome (4322102012234).

The spelling of 1212101000113 in words is "one trillion, two hundred twelve billion, one hundred one million, one hundred thirteen", and thus it is an aban number.