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121210118010131 is a prime number
BaseRepresentation
bin11011100011110101101110…
…000001101111010100010011
3120220011120111112022022111212
4123203311232001233110103
5111341401310202311011
61105443054241330335
734350066501435053
oct3343655601572423
9526146445268455
10121210118010131
1135691a16748047
12117173bb3369ab
1352830accb0107
1421d085b279563
15e02e4776008b
hex6e3d6e06f513

121210118010131 has 2 divisors, whose sum is σ = 121210118010132. Its totient is φ = 121210118010130.

The previous prime is 121210118010001. The next prime is 121210118010139. The reversal of 121210118010131 is 131010811012121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121210118010131 - 210 = 121210118009107 is a prime.

It is a super-2 number, since 2×1212101180101312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121210118010097 and 121210118010106.

It is not a weakly prime, because it can be changed into another prime (121210118010139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605059005065 + 60605059005066.

It is an arithmetic number, because the mean of its divisors is an integer number (60605059005066).

Almost surely, 2121210118010131 is an apocalyptic number.

121210118010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

121210118010131 is an equidigital number, since it uses as much as digits as its factorization.

121210118010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 23.

Adding to 121210118010131 its reverse (131010811012121), we get a palindrome (252220929022252).

The spelling of 121210118010131 in words is "one hundred twenty-one trillion, two hundred ten billion, one hundred eighteen million, ten thousand, one hundred thirty-one".