Base | Representation |
---|---|
bin | 11011100011110101101110… |
… | …010001110000111001010011 |
3 | 120220011120111211012201212212 |
4 | 123203311232101300321103 |
5 | 111341401312241222044 |
6 | 1105443054511342335 |
7 | 34350066552232151 |
oct | 3343655621607123 |
9 | 526146454181785 |
10 | 121210122210899 |
11 | 35691a19057157 |
12 | 117174008219ab |
13 | 52830b0b21187 |
14 | 21d085ba503d1 |
15 | e02e47cdea9e |
hex | 6e3d6e470e53 |
121210122210899 has 2 divisors, whose sum is σ = 121210122210900. Its totient is φ = 121210122210898.
The previous prime is 121210122210851. The next prime is 121210122210901. The reversal of 121210122210899 is 998012221012121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121210122210899 is a prime.
Together with 121210122210901, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (121210124210899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605061105449 + 60605061105450.
It is an arithmetic number, because the mean of its divisors is an integer number (60605061105450).
Almost surely, 2121210122210899 is an apocalyptic number.
121210122210899 is a deficient number, since it is larger than the sum of its proper divisors (1).
121210122210899 is an equidigital number, since it uses as much as digits as its factorization.
121210122210899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 41.
It can be divided in two parts, 1212101222 and 10899, that added together give a palindrome (1212112121).
The spelling of 121210122210899 in words is "one hundred twenty-one trillion, two hundred ten billion, one hundred twenty-two million, two hundred ten thousand, eight hundred ninety-nine".
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