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121210220209873 is a prime number
BaseRepresentation
bin11011100011110101110100…
…000111100110011011010001
3120220011120202122121121012111
4123203311310013212123101
5111341402012333203443
61105443112332025321
734350102152221354
oct3343656407463321
9526146678547174
10121210220209873
1135691a69401243
1211717429602241
1352830c8213c32
1421d086aa8029b
15e02e516eb69d
hex6e3d741e66d1

121210220209873 has 2 divisors, whose sum is σ = 121210220209874. Its totient is φ = 121210220209872.

The previous prime is 121210220209811. The next prime is 121210220209879. The reversal of 121210220209873 is 378902022012121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75864918742209 + 45345301467664 = 8710047^2 + 6733892^2 .

It is a cyclic number.

It is not a de Polignac number, because 121210220209873 - 245 = 86025848121041 is a prime.

It is a super-2 number, since 2×1212102202098732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121210220209879) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605110104936 + 60605110104937.

It is an arithmetic number, because the mean of its divisors is an integer number (60605110104937).

Almost surely, 2121210220209873 is an apocalyptic number.

It is an amenable number.

121210220209873 is a deficient number, since it is larger than the sum of its proper divisors (1).

121210220209873 is an equidigital number, since it uses as much as digits as its factorization.

121210220209873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 40.

The spelling of 121210220209873 in words is "one hundred twenty-one trillion, two hundred ten billion, two hundred twenty million, two hundred nine thousand, eight hundred seventy-three".