Base | Representation |
---|---|
bin | 11011100011110110100011… |
… | …001100110101101001111010 |
3 | 120220011122210200221210101100 |
4 | 123203312203030311221322 |
5 | 111341410122042041442 |
6 | 1105443322550232230 |
7 | 34350130553250360 |
oct | 3343664314655172 |
9 | 526148720853340 |
10 | 121211010112122 |
11 | 35692334275517 |
12 | 1171760a055676 |
13 | 52831c2a6c908 |
14 | 21d090393b630 |
15 | e02e9ac2b84c |
hex | 6e3da3335a7a |
121211010112122 has 48 divisors (see below), whose sum is σ = 309823534305792. Its totient is φ = 33514565006880.
The previous prime is 121211010112081. The next prime is 121211010112139. The reversal of 121211010112122 is 221211010112121.
It is a happy number.
121211010112122 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1212110101121222 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 121211010112095 and 121211010112104.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15515998413 + ... + 15516006224.
It is an arithmetic number, because the mean of its divisors is an integer number (6454656964704).
Almost surely, 2121211010112122 is an apocalyptic number.
121211010112122 is an abundant number, since it is smaller than the sum of its proper divisors (188612524193670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121211010112122 is a wasteful number, since it uses less digits than its factorization.
121211010112122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31032004683 (or 31032004680 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 18.
Adding to 121211010112122 its reverse (221211010112121), we get a palindrome (342422020224243).
Subtracting 121211010112122 from its reverse (221211010112121), we obtain a palindrome (99999999999999).
The spelling of 121211010112122 in words is "one hundred twenty-one trillion, two hundred eleven billion, ten million, one hundred twelve thousand, one hundred twenty-two".
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