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12121110982433 is a prime number
BaseRepresentation
bin1011000001100010101010…
…0000111010111100100001
31120220202201001202110200102
42300120222200322330201
53042043013402414213
641440210030432145
72360502300251525
oct260305240727441
946822631673612
1012121110982433
113953597175522
12143919b662655
1369c028b016bb
142dc9446c1d85
151604706cb158
hexb062a83af21

12121110982433 has 2 divisors, whose sum is σ = 12121110982434. Its totient is φ = 12121110982432.

The previous prime is 12121110982417. The next prime is 12121110982439. The reversal of 12121110982433 is 33428901112121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6334045663009 + 5787065319424 = 2516753^2 + 2405632^2 .

It is a cyclic number.

It is not a de Polignac number, because 12121110982433 - 24 = 12121110982417 is a prime.

It is not a weakly prime, because it can be changed into another prime (12121110982439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060555491216 + 6060555491217.

It is an arithmetic number, because the mean of its divisors is an integer number (6060555491217).

Almost surely, 212121110982433 is an apocalyptic number.

It is an amenable number.

12121110982433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12121110982433 is an equidigital number, since it uses as much as digits as its factorization.

12121110982433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 38.

The spelling of 12121110982433 in words is "twelve trillion, one hundred twenty-one billion, one hundred ten million, nine hundred eighty-two thousand, four hundred thirty-three".