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121211433001 is a prime number
BaseRepresentation
bin111000011100011000…
…0111011000000101001
3102120212102200210011101
41300320300323000221
53441220111324001
6131403405401401
711520506116021
oct1607060730051
9376772623141
10121211433001
114745076a71a
121b5a9569261
13b579182729
145c1c1b0a81
1532464eda01
hex1c38c3b029

121211433001 has 2 divisors, whose sum is σ = 121211433002. Its totient is φ = 121211433000.

The previous prime is 121211432999. The next prime is 121211433011. The reversal of 121211433001 is 100334112121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 62838456976 + 58372976025 = 250676^2 + 241605^2 .

It is a cyclic number.

It is not a de Polignac number, because 121211433001 - 21 = 121211432999 is a prime.

It is a super-2 number, since 2×1212114330012 (a number of 23 digits) contains 22 as substring.

Together with 121211432999, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 121211433001.

It is not a weakly prime, because it can be changed into another prime (121211433011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605716500 + 60605716501.

It is an arithmetic number, because the mean of its divisors is an integer number (60605716501).

Almost surely, 2121211433001 is an apocalyptic number.

It is an amenable number.

121211433001 is a deficient number, since it is larger than the sum of its proper divisors (1).

121211433001 is an equidigital number, since it uses as much as digits as its factorization.

121211433001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 121211433001 its reverse (100334112121), we get a palindrome (221545545122).

The spelling of 121211433001 in words is "one hundred twenty-one billion, two hundred eleven million, four hundred thirty-three thousand, one".