Base | Representation |
---|---|
bin | 1011000001100011000001… |
… | …1111001110011001100011 |
3 | 1120220202222001100002212202 |
4 | 2300120300133032121203 |
5 | 3042043220031413443 |
6 | 41440224010443415 |
7 | 2360504625144353 |
oct | 260306037163143 |
9 | 46822861302782 |
10 | 12121211201123 |
11 | 39536387a6292 |
12 | 143920913356b |
13 | 69c0437c08bb |
14 | 2dc953b2cb63 |
15 | 1604793c57b8 |
hex | b06307ce663 |
12121211201123 has 2 divisors, whose sum is σ = 12121211201124. Its totient is φ = 12121211201122.
The previous prime is 12121211201119. The next prime is 12121211201159. The reversal of 12121211201123 is 32110211212121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12121211201123 - 22 = 12121211201119 is a prime.
It is a super-2 number, since 2×121212112011232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12121211201095 and 12121211201104.
It is not a weakly prime, because it can be changed into another prime (12121211201923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060605600561 + 6060605600562.
It is an arithmetic number, because the mean of its divisors is an integer number (6060605600562).
Almost surely, 212121211201123 is an apocalyptic number.
12121211201123 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121211201123 is an equidigital number, since it uses as much as digits as its factorization.
12121211201123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 12121211201123 its reverse (32110211212121), we get a palindrome (44231422413244).
The spelling of 12121211201123 in words is "twelve trillion, one hundred twenty-one billion, two hundred eleven million, two hundred one thousand, one hundred twenty-three".
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