Base | Representation |
---|---|
bin | 10001101000111000110… |
… | …001100111111010110110 |
3 | 11021212201122200010110021 |
4 | 101220320301213322312 |
5 | 124324422111411014 |
6 | 2324502451315354 |
7 | 153400536065035 |
oct | 21507061477266 |
9 | 4255648603407 |
10 | 1212133310134 |
11 | 42807672062a |
12 | 176b04babb5a |
13 | 8a3c4256866 |
14 | 4294bb2871c |
15 | 217e4ee0624 |
hex | 11a38c67eb6 |
1212133310134 has 4 divisors (see below), whose sum is σ = 1818199965204. Its totient is φ = 606066655066.
The previous prime is 1212133310111. The next prime is 1212133310137. The reversal of 1212133310134 is 4310133312121.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1212133310099 and 1212133310108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1212133310137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303033327532 + ... + 303033327535.
It is an arithmetic number, because the mean of its divisors is an integer number (454549991301).
Almost surely, 21212133310134 is an apocalyptic number.
1212133310134 is a deficient number, since it is larger than the sum of its proper divisors (606066655070).
1212133310134 is an equidigital number, since it uses as much as digits as its factorization.
1212133310134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606066655069.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1212133310134 its reverse (4310133312121), we get a palindrome (5522266622255).
The spelling of 1212133310134 in words is "one trillion, two hundred twelve billion, one hundred thirty-three million, three hundred ten thousand, one hundred thirty-four".
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