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1212144433 is a prime number
BaseRepresentation
bin100100000111111…
…1101101100110001
310010110212022120021
41020033331230301
54440302110213
6320140243441
742016025533
oct11017755461
93113768507
101212144433
11572251065
12299b40581
13164187136
14b6db1853
1571638d8d
hex483fdb31

1212144433 has 2 divisors, whose sum is σ = 1212144434. Its totient is φ = 1212144432.

The previous prime is 1212144389. The next prime is 1212144443. The reversal of 1212144433 is 3344412121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1125132849 + 87011584 = 33543^2 + 9328^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1212144433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212144398 and 1212144407.

It is not a weakly prime, because it can be changed into another prime (1212144443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606072216 + 606072217.

It is an arithmetic number, because the mean of its divisors is an integer number (606072217).

Almost surely, 21212144433 is an apocalyptic number.

It is an amenable number.

1212144433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212144433 is an equidigital number, since it uses as much as digits as its factorization.

1212144433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 25.

The square root of 1212144433 is about 34815.8646740247. The cubic root of 1212144433 is about 1066.2313728526.

Adding to 1212144433 its reverse (3344412121), we get a palindrome (4556556554).

The spelling of 1212144433 in words is "one billion, two hundred twelve million, one hundred forty-four thousand, four hundred thirty-three".