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121215303411997 is a prime number
BaseRepresentation
bin11011100011111010100011…
…000110011110100100011101
3120220012001212220120000121211
4123203322203012132210131
5111341442420133140442
61105445312554424421
734350342134556544
oct3343724306364435
9526161786500554
10121215303411997
1135694137777233
1211718407a32111
135283728384542
1421d0bcdbdd15b
15e0314cada617
hex6e3ea319e91d

121215303411997 has 2 divisors, whose sum is σ = 121215303411998. Its totient is φ = 121215303411996.

The previous prime is 121215303411947. The next prime is 121215303412033. The reversal of 121215303411997 is 799114303512121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109476587167236 + 11738716244761 = 10463106^2 + 3426181^2 .

It is a cyclic number.

It is not a de Polignac number, because 121215303411997 - 227 = 121215169194269 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121215303411997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121215303411947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60607651705998 + 60607651705999.

It is an arithmetic number, because the mean of its divisors is an integer number (60607651705999).

Almost surely, 2121215303411997 is an apocalyptic number.

It is an amenable number.

121215303411997 is a deficient number, since it is larger than the sum of its proper divisors (1).

121215303411997 is an equidigital number, since it uses as much as digits as its factorization.

121215303411997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 408240, while the sum is 49.

The spelling of 121215303411997 in words is "one hundred twenty-one trillion, two hundred fifteen billion, three hundred three million, four hundred eleven thousand, nine hundred ninety-seven".