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12122003420143 = 101131916181953
BaseRepresentation
bin1011000001100101111110…
…1101010011001111101111
31120220212000021001000001221
42300121133231103033233
53042101330333421033
641440434350444211
72360533354662661
oct260313755231757
946825007030057
1012122003420143
113953a04a02151
1214393aa503667
1369c13b97ac56
142dc9cb030531
151604c3c1212d
hexb065fb533ef

12122003420143 has 8 divisors (see below), whose sum is σ = 12335473828656. Its totient is φ = 11910365376000.

The previous prime is 12122003420101. The next prime is 12122003420159. The reversal of 12122003420143 is 34102430022121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12122003420143 - 213 = 12122003411951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12122003420243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 458077746 + ... + 458104207.

It is an arithmetic number, because the mean of its divisors is an integer number (1541934228582).

Almost surely, 212122003420143 is an apocalyptic number.

12122003420143 is a deficient number, since it is larger than the sum of its proper divisors (213470408513).

12122003420143 is a wasteful number, since it uses less digits than its factorization.

12122003420143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 916182185.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12122003420143 its reverse (34102430022121), we get a palindrome (46224433442264).

The spelling of 12122003420143 in words is "twelve trillion, one hundred twenty-two billion, three million, four hundred twenty thousand, one hundred forty-three".

Divisors: 1 101 131 13231 916181953 92534377253 120019835843 12122003420143