12122011043 has 2 divisors, whose sum is σ = 12122011044. Its totient is φ = 12122011042.

The previous prime is 12122011009. The next prime is 12122011051. The reversal of 12122011043 is 34011022121.

12122011043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34011022121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12122011043 - 2¹⁴ = 12121994659 is a prime.

It is a super-2 number, since 2×12122011043² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12122011093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061005521 + 6061005522.

It is an arithmetic number, because the mean of its divisors is an integer number (6061005522).

Almost surely, 2^12122011043 is an apocalyptic number.

12122011043 is a deficient number, since it is larger than the sum of its proper divisors (1).

12122011043 is an equidigital number, since it uses as much as digits as its factorization.

12122011043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12122011043 its reverse (34011022121), we get a palindrome (46133033164).

The spelling of 12122011043 in words is "twelve billion, one hundred twenty-two million, eleven thousand, forty-three".