Base | Representation |
---|---|
bin | 1011000001100110000000… |
… | …1110000010000010011011 |
3 | 1120220212000212011220222122 |
4 | 2300121200032002002123 |
5 | 3042101340033003121 |
6 | 41440435254411455 |
7 | 2360533520630225 |
oct | 260314016020233 |
9 | 46825025156878 |
10 | 12122012000411 |
11 | 3953a09832685 |
12 | 14393b1360b8b |
13 | 69c140693531 |
14 | 2dc9cc225415 |
15 | 1604c48595ab |
hex | b066038209b |
12122012000411 has 2 divisors, whose sum is σ = 12122012000412. Its totient is φ = 12122012000410.
The previous prime is 12122012000407. The next prime is 12122012000431. The reversal of 12122012000411 is 11400021022121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12122012000411 - 22 = 12122012000407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12122012000411.
It is not a weakly prime, because it can be changed into another prime (12122012000401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061006000205 + 6061006000206.
It is an arithmetic number, because the mean of its divisors is an integer number (6061006000206).
Almost surely, 212122012000411 is an apocalyptic number.
12122012000411 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122012000411 is an equidigital number, since it uses as much as digits as its factorization.
12122012000411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 12122012000411 its reverse (11400021022121), we get a palindrome (23522033022532).
The spelling of 12122012000411 in words is "twelve trillion, one hundred twenty-two billion, twelve million, four hundred eleven", and thus it is an aban number.
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