Base | Representation |
---|---|
bin | 11011100011111111000011… |
… | …000000101110010111100011 |
3 | 120220012112100112200012202221 |
4 | 123203333003000232113203 |
5 | 111342032313214221201 |
6 | 1105451432145251511 |
7 | 34350602626651501 |
oct | 3343770300562743 |
9 | 526175315605687 |
10 | 121220133742051 |
11 | 35696196327743 |
12 | 11719335633b97 |
13 | 52840180180c6 |
14 | 21d112b535671 |
15 | e03331bc94a1 |
hex | 6e3fc302e5e3 |
121220133742051 has 2 divisors, whose sum is σ = 121220133742052. Its totient is φ = 121220133742050.
The previous prime is 121220133742039. The next prime is 121220133742111. The reversal of 121220133742051 is 150247331022121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121220133742051 - 27 = 121220133741923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121220133741998 and 121220133742016.
It is not a weakly prime, because it can be changed into another prime (121220133742451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610066871025 + 60610066871026.
It is an arithmetic number, because the mean of its divisors is an integer number (60610066871026).
Almost surely, 2121220133742051 is an apocalyptic number.
121220133742051 is a deficient number, since it is larger than the sum of its proper divisors (1).
121220133742051 is an equidigital number, since it uses as much as digits as its factorization.
121220133742051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 121220133742051 its reverse (150247331022121), we get a palindrome (271467464764172).
The spelling of 121220133742051 in words is "one hundred twenty-one trillion, two hundred twenty billion, one hundred thirty-three million, seven hundred forty-two thousand, fifty-one".
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