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12122051874703 is a prime number
BaseRepresentation
bin1011000001100110001010…
…0110001000111110001111
31120220212010122012202020021
42300121202212020332033
53042101430234442303
641440443241203011
72360534513562631
oct260314246107617
946825118182207
1012122051874703
113953a2a297841
121439402790467
1369c148a14aa4
142dc9d3644a51
151604c80d3ebd
hexb0662988f8f

12122051874703 has 2 divisors, whose sum is σ = 12122051874704. Its totient is φ = 12122051874702.

The previous prime is 12122051874689. The next prime is 12122051874739. The reversal of 12122051874703 is 30747815022121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12122051874703 - 241 = 9923028619151 is a prime.

It is a super-2 number, since 2×121220518747032 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12122051874703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12122051874763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061025937351 + 6061025937352.

It is an arithmetic number, because the mean of its divisors is an integer number (6061025937352).

Almost surely, 212122051874703 is an apocalyptic number.

12122051874703 is a deficient number, since it is larger than the sum of its proper divisors (1).

12122051874703 is an equidigital number, since it uses as much as digits as its factorization.

12122051874703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 188160, while the sum is 43.

Adding to 12122051874703 its reverse (30747815022121), we get a palindrome (42869866896824).

The spelling of 12122051874703 in words is "twelve trillion, one hundred twenty-two billion, fifty-one million, eight hundred seventy-four thousand, seven hundred three".