Base | Representation |
---|---|
bin | 10001101000111101010… |
… | …110001101111111011111 |
3 | 11021212220222222222210211 |
4 | 101220331112031333133 |
5 | 124330101230342002 |
6 | 2324514231313251 |
7 | 153402460044022 |
oct | 21507526157737 |
9 | 4255828888724 |
10 | 1212210012127 |
11 | 428105a49a04 |
12 | 176b2681b827 |
13 | 8a407100a5a |
14 | 42957db31b9 |
15 | 217ebae1dd7 |
hex | 11a3d58dfdf |
1212210012127 has 2 divisors, whose sum is σ = 1212210012128. Its totient is φ = 1212210012126.
The previous prime is 1212210012119. The next prime is 1212210012227. The reversal of 1212210012127 is 7212100122121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1212210012127 - 23 = 1212210012119 is a prime.
It is a super-2 number, since 2×12122100121272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1212210012098 and 1212210012107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212210012227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606105006063 + 606105006064.
It is an arithmetic number, because the mean of its divisors is an integer number (606105006064).
Almost surely, 21212210012127 is an apocalyptic number.
1212210012127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212210012127 is an equidigital number, since it uses as much as digits as its factorization.
1212210012127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 1212210012127 its reverse (7212100122121), we get a palindrome (8424310134248).
The spelling of 1212210012127 in words is "one trillion, two hundred twelve billion, two hundred ten million, twelve thousand, one hundred twenty-seven".
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