Base | Representation |
---|---|
bin | 1011000001100110010110… |
… | …0011010101100101000111 |
3 | 1120220212021002112112022212 |
4 | 2300121211203111211013 |
5 | 3042102030434042214 |
6 | 41440452212214035 |
7 | 2360535655261112 |
oct | 260314543254507 |
9 | 46825232475285 |
10 | 12122101471559 |
11 | 3953a55292682 |
12 | 143941730a31b |
13 | 69c15608b841 |
14 | 2dc9da075579 |
15 | 1604cc62e53e |
hex | b06658d5947 |
12122101471559 has 2 divisors, whose sum is σ = 12122101471560. Its totient is φ = 12122101471558.
The previous prime is 12122101471499. The next prime is 12122101471573. The reversal of 12122101471559 is 95517410122121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12122101471559 - 28 = 12122101471303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12122101471859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061050735779 + 6061050735780.
It is an arithmetic number, because the mean of its divisors is an integer number (6061050735780).
Almost surely, 212122101471559 is an apocalyptic number.
12122101471559 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122101471559 is an equidigital number, since it uses as much as digits as its factorization.
12122101471559 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 41.
The spelling of 12122101471559 in words is "twelve trillion, one hundred twenty-two billion, one hundred one million, four hundred seventy-one thousand, five hundred fifty-nine".
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