Base | Representation |
---|---|
bin | 10001101000111101011… |
… | …010011110111011100011 |
3 | 11021212221002002210100121 |
4 | 101220331122132323203 |
5 | 124330102022130313 |
6 | 2324514311301111 |
7 | 153402502411252 |
oct | 21507532367343 |
9 | 4255832083317 |
10 | 1212211130083 |
11 | 428106642938 |
12 | 176b2707a797 |
13 | 8a407402875 |
14 | 429581c4799 |
15 | 217ebc6328d |
hex | 11a3d69eee3 |
1212211130083 has 2 divisors, whose sum is σ = 1212211130084. Its totient is φ = 1212211130082.
The previous prime is 1212211130057. The next prime is 1212211130147. The reversal of 1212211130083 is 3800311122121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1212211130083 - 217 = 1212210999011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1212211136083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606105565041 + 606105565042.
It is an arithmetic number, because the mean of its divisors is an integer number (606105565042).
Almost surely, 21212211130083 is an apocalyptic number.
1212211130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212211130083 is an equidigital number, since it uses as much as digits as its factorization.
1212211130083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
The spelling of 1212211130083 in words is "one trillion, two hundred twelve billion, two hundred eleven million, one hundred thirty thousand, eighty-three".
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