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121221201101053 is a prime number
BaseRepresentation
bin11011100100000000000010…
…101000011000000011111101
3120220012122002221002200001211
4123210000002220120003331
5111342042004440213203
61105452130114404421
734350641240236354
oct3344000250300375
9526178087080054
10121221201101053
1135696693878319
1211719592b90711
1352841581aa991
1421d11cd1b899b
15e03395763c6d
hex6e4002a180fd

121221201101053 has 2 divisors, whose sum is σ = 121221201101054. Its totient is φ = 121221201101052.

The previous prime is 121221201100969. The next prime is 121221201101087. The reversal of 121221201101053 is 350101102122121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78725639326009 + 42495561775044 = 8872747^2 + 6518862^2 .

It is a cyclic number.

It is not a de Polignac number, because 121221201101053 - 221 = 121221199003901 is a prime.

It is a super-3 number, since 3×1212212011010533 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121221201101953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610600550526 + 60610600550527.

It is an arithmetic number, because the mean of its divisors is an integer number (60610600550527).

Almost surely, 2121221201101053 is an apocalyptic number.

It is an amenable number.

121221201101053 is a deficient number, since it is larger than the sum of its proper divisors (1).

121221201101053 is an equidigital number, since it uses as much as digits as its factorization.

121221201101053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 121221201101053 its reverse (350101102122121), we get a palindrome (471322303223174).

The spelling of 121221201101053 in words is "one hundred twenty-one trillion, two hundred twenty-one billion, two hundred one million, one hundred one thousand, fifty-three".