Base | Representation |
---|---|
bin | 1011000001100110011011… |
… | …0010000001110100011111 |
3 | 1120220212022112100120020011 |
4 | 2300121212302001310133 |
5 | 3042102101224144444 |
6 | 41440454230304051 |
7 | 2360536325515252 |
oct | 260314662016437 |
9 | 46825275316204 |
10 | 12122122099999 |
11 | 3953a659a207a |
12 | 14394221b8027 |
13 | 69c15a432012 |
14 | 2dc9dcac5099 |
15 | 1604ce356734 |
hex | b0666c81d1f |
12122122099999 has 2 divisors, whose sum is σ = 12122122100000. Its totient is φ = 12122122099998.
The previous prime is 12122122099993. The next prime is 12122122100069. The reversal of 12122122099999 is 99999022122121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12122122099999 - 233 = 12113532165407 is a prime.
It is a super-3 number, since 3×121221220999993 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12122122099993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061061049999 + 6061061050000.
It is an arithmetic number, because the mean of its divisors is an integer number (6061061050000).
Almost surely, 212122122099999 is an apocalyptic number.
12122122099999 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122122099999 is an equidigital number, since it uses as much as digits as its factorization.
12122122099999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1889568, while the sum is 58.
The spelling of 12122122099999 in words is "twelve trillion, one hundred twenty-two billion, one hundred twenty-two million, ninety-nine thousand, nine hundred ninety-nine".
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