Base | Representation |
---|---|
bin | 111000011100101011… |
… | …0111111100100011011 |
3 | 102120220010110211100102 |
4 | 1300321112333210123 |
5 | 3441230140210042 |
6 | 131404403330015 |
7 | 11520660003452 |
oct | 1607126774433 |
9 | 376803424312 |
10 | 121221413147 |
11 | 4745636697a |
12 | 1b5b098090b |
13 | b57b268243 |
14 | 5c1d64bb99 |
15 | 3247320b32 |
hex | 1c395bf91b |
121221413147 has 2 divisors, whose sum is σ = 121221413148. Its totient is φ = 121221413146.
The previous prime is 121221413101. The next prime is 121221413161. The reversal of 121221413147 is 741314122121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121221413147 - 212 = 121221409051 is a prime.
It is not a weakly prime, because it can be changed into another prime (121221413347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610706573 + 60610706574.
It is an arithmetic number, because the mean of its divisors is an integer number (60610706574).
Almost surely, 2121221413147 is an apocalyptic number.
121221413147 is a deficient number, since it is larger than the sum of its proper divisors (1).
121221413147 is an equidigital number, since it uses as much as digits as its factorization.
121221413147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2688, while the sum is 29.
Adding to 121221413147 its reverse (741314122121), we get a palindrome (862535535268).
The spelling of 121221413147 in words is "one hundred twenty-one billion, two hundred twenty-one million, four hundred thirteen thousand, one hundred forty-seven".
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